A six-cylinder Otto cycle engine has a compression ratio of (9.3):1. The diamete
ID: 1322611 • Letter: A
Question
A six-cylinder Otto cycle engine has a compression ratio of (9.3):1. The diameter of each cylinder, called the bore of the engine, is 82.2 mm. The distance the piston moves during compression, called the stroke of the engine, is 86.5 mm, making the height of the cylinder 96.922 mm. The initial absolute pressure of the air-fuel mixture (point a on the p-v diagram) is 8.10e+4 Pa and the initial temperature is 291 K. 198 J of heat is added to each cylinder in each cycle by burning gasoline. The gas has c?v = 20.8 J/mol-K and ? = 1.40. Answer the following questions for one cylinder of the engine.
A.) Calculate the volume of the air-fuel mixture at the end of the compression stroke (point b on the p-v diagram). (include units with answer)
B.) Calculate the pressure of the air-fuel mixture at the end of the compression stroke (point b on the p-v diagram). (include units with answer)
C.) Calculate the temperature of the air-fuel mixture at the end of the compression stroke (point b on the p-v diagram). (include units with answer)
D.) Calculate the temperature at the end of combustion (point c on the p-v diagram). (include units with answer)
E.) Calculate the pressure at the end of combustion (point c on the p-v diagram). (include units with answer)
F.) Calculate the temperature at the end of expansion (point d on the p-v diagram). (include units with answer)
G.) Calculate the magnitude of Qc, the amount of heat lost in cooling. (include units with answer)
H.) Calculate the work done during compression (a-b on the p-v diagram). (include units with answer)
I.) Calculate the work done during combustion (b-c on the p-v diagram). (include units with answer)
J.) Calculate the work done during expansion (c-d on the p-v diagram). (include units with answer)
k.) Calculate the work done during cooling (d-a on the p-v diagram). (include units with answer)
l.) Calculate the efficiency of the engine. (%)
I will rate, please just show work along with answers so i can understand
Explanation / Answer
apply ideal gas equation PV = nRT
so
part A:
V = nRT/P
where n is no. of moles
R is cosnatnt = 8,314
T is temp
P is pressure