Part A For the circuit shown in the figure(Figure 1) find the current through ea

Question

Part A

For the circuit shown in the figure(Figure 1) find the current through each resistor.

PART B

For the circuit shown in the figure find the potential difference across each resistor.

Express your answers using two significant figures. Enter your answers numerically separated by commas.

Part A For the circuit shown in the figure(Figure 1) find the current through each resistor. PART B For the circuit shown in the figure find the potential difference across each resistor. Express your answers using two significant figures. Enter your answers numerically separated by commas.

Explanation / Answer

Rnet in sereis Rs = R1+R2

Rnet in parallel Rp = R1R2/(R1+R2)

so

6 and 12 are in parallel-----< 12*6/18 = 4 ohms

4 is in series with 4 ohms = 8 ohms

8 is in parallel with 8 =Rp = 4 ohms

4 is in series 2 ohms

so Rnet = 4+2 = 6 ohms

Inet = V/R = 24/6 = 4 Amps

same current passes in series combination and same pD exists across parallel Combination

so

Inet = Iacross2 = I across 4 = 4 Amps

as V across 2 ohms = iR = 4* 2 = 8 Volts

so volatge across set of (6,4,12,8) is 24-8 = 16 V

Vacross (4,6,12) = V8 =    16 V

RNet ( 4, 6,12) = 8 ohms

so i across (4.6,12 ) = i4 = I6,12 = V/R = 16/8 = 2 Amps

I across 8 = V/R = 16/8 = 2Amps

Current across 4 ohms = 16/4 = 4 Amps

i across 6 and 12 = 2 Amps

Rnet = 6,12 = 4 ohms

V across 4 ohms = 16 -8 = 8 V

V across 6, 12 = V across 6 = V across 12 = 8 Volts

iacross 6 = 8/6 = 1.334 Amps

i across 12 = 8/12 =0.667 Amps

so the answers are

Current across

2 ohms is 4 Amps

4 ohms is 4 Amps

6 ohms is 1.33Amps

12 ohms is 0.667 Amps

8 ohms is 2 Amps

V across

2ohms is 8V

4 ohms is 16

6 ohms is 8 V

12 ohms is 8 V

8 ohms is 16 V

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