In the diagram below, circularly polarized light is incident on two quarter1wave

Question

In the diagram below, circularly polarized light is incident on two quarter1wave plates for which nparallel>nperpendicular . The electric field of the incident light is rotat ing counterclockwise, as viewed from the right. The magnitude of this electric field is a c onstant value of 40 V/m.

(b) In the region between the two plates, what angl e does the maximum electric field vector make with the y-axis? What is the maximum electric field strength in this region?

(c) The optic axis of the second quarter1wave plate is vertical. What type of polarization emerges from the second quarter-wave plate: circula r, linear, or elliptical? On the figure below, draw some pictures to show how the nature of the po larization changes as the light passes through the quarter1wave plate.

In the diagram below, circularly polarized light is incident on two quarter1wave plates for which nparallel > nperpendicular . The electric field of the incident light is rotat ing counterclockwise, as viewed from the right. The magnitude of this electric field is a constant value of 40 V/m. (a) The optic axis of the first quarter1wave plate makes angle alpha = 25 with the y-axis. What type of polarization emerges from the first quarter1wave plate: circular, linear, or elliptical? On the figure below, draw some pictures to show how the na ture of the polarization changes as the light passes through the quarter-wave plate. (b) In the region between the two plates, what angl e does the maximum electric field vector make with the y-axis? What is the maximum electric field strength in this region? (c) The optic axis of the second quarter1wave plate is vertical. What type of polarization emerges from the second quarter-wave plate: circula r, linear, or elliptical? On the figure below, draw some pictures to show how the nature of the po larization changes as the light passes through the quarter1wave plate. (d) What is the maximum electric field strength of the light that emerges from the second quarter-wa

Explanation / Answer

electric fields and Intensity are rel;ated by

I = Emax^2/2uoC

so

I = 40*40/(2* 4*3.14 e-7 * 3e8)

I = 2.12

apply malus law as I = Io cos^2 theta

so I = 2.123 cos^2(25)

I = 1.74 W/m^2

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---