In the diagram below the capacitor has a capacitance of94 F and the inductor has
ID: 1669410 • Letter: I
Question
In the diagram below the capacitor has a capacitance of94 F and the inductor has aninductance of 21 mH. Initially thecapacitor has a voltage of 25 V. Thiscircuit has no resistance.A. How much charge does the capacitorinitially have?
B. How much energy does the capacitor initiallyhave?
C. What is the maximum current that will passthrough the inductor?
D. This kind of circuit can best be described asa...(choose one) 1 ParallelCircuit 2 Simple HarmonicOscillator 3 Series RCLCircuit 4 SemiconductorDevice 1 ParallelCircuit 2 Simple HarmonicOscillator 3 Series RCLCircuit 4 SemiconductorDevice 1 ParallelCircuit 2 Simple HarmonicOscillator 3 Series RCLCircuit 4 SemiconductorDevice
Explanation / Answer
A. How much charge does the capacitorinitially have? .Q = CV = 94 uF * 25 V = 2350 uC or 0.002350 Coulomb .
B. How much energy does the capacitor initiallyhave?
.
Energy = (1/2) CV2 = (1/2) * 94 x 10-6 * 252 = 0.0294Joules .
C. What is the maximum current that will passthrough the inductor?
Energy of inductor = (1/2) Li2 so max current will occur when all of the energy is stored in theinductor . 0.0294 = (1/2) * 0.021 *i2 i = 1.67 A is the max current .
D. This kind of circuit can best be described asa...(choose one) . 1 ParallelCircuit 2 Simple HarmonicOscillator 3 Series RCLCircuit 4 SemiconductorDevice 1 ParallelCircuit 2 Simple HarmonicOscillator 3 Series RCLCircuit 4 SemiconductorDevice 1 ParallelCircuit 2 Simple HarmonicOscillator 3 Series RCLCircuit 4 SemiconductorDevice . SIMPLE HARMONICOSCILLATOR