Part A: A velocity vector 49 above the positive x -axis has a y -component of 15

Question

Part A: A velocity vector 49 above the positive x-axis has a y-component of 15 m/s .

What is the value of its x-component?

Part B: Jack and Jill ran up the hill at 3.2 m/s . The horizontal component of Jill's velocity vector was 2.4 m/s .

1. What was the angle of the hill?

2. What was the vertical component of Jill's velocity?

Part c: A cannon tilted upward at = 34 fires a cannonball with a speed of 96 m/s

1. At that instant, what is the component of the cannonball’s velocity parallel to the ground?

Explanation / Answer

Part A

Vsin(49)= 15

So V = 15/sin(49)

so x componant = Vcos(49) = 15/sin(49) *cos(49) = 15 cot(49) = 13.03 m/sec

B)

horizontal componant = 3.2 cos(theta) = 2.4

theta = 41.41 degree

vertical componant = 3.2 *sin(41.41) = 2.116 m/sec

Part c

cannonball’s velocity parallel to the ground = 96 *cos(34) = 79.587 m/sec

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