A metal tool is sharpened by being held against the rim of a wheel on a grinding

Question

A metal tool is sharpened by being held against the rim of a wheel on a grinding machine by a force of 180 N. The frictional force between the rim and the tool grind off small pieces of the tool. The wheel has a radius of 20.0 cm and rotates at 2.5 rev/s. The coefficient of kinetic friction between the wheel and the tool is 0.320. At what rate is energy being transferred from the motor driving the wheel to the thermal energy of the wheel and tool and to the kinetic energy of the material thrown from the tool?

Explanation / Answer

frictional forc f= u*F

torque = r*f

power = torque * angular speed

P = r*f*w

r = radius = 0.2 m

w = 2.5 rev/s = 2.5*2*pi rad/s

P = 0.2*0.32*180*2.5*2*pi

P = 181 W <<--------answer

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