Part A If the elevator has an upward acceleration of 2.25 m/s2 and the balance r

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Part A

If the elevator has an upward acceleration of 2.25 m/s2 and the balance reads 70.0 N , what is the true weight of the fish?

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Part B

Under what circumstances will the balance read 36.0 N ?

We take the positive direction of the acceleration to be upward.

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Part C

What will the balance read if the elevator cable breaks?

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A large fish hangs from a spring balance supported from the roof of an elevator.

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Part A

If the elevator has an upward acceleration of 2.25 m/s2 and the balance reads 70.0 N , what is the true weight of the fish?

Wtrue =   N  

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Part B

Under what circumstances will the balance read 36.0 N ?

We take the positive direction of the acceleration to be upward.

acceleration of the elevator =   m/s2  

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Part C

What will the balance read if the elevator cable breaks?

F =   N  

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Explanation / Answer

A) When elevator accelerate upwards,

W_apparent = W_true + m*a

W_apparanet = m*g + m*a

W_apparent = m*(g+a)

m = W_apparent/(g+a)

= 70/(2.25+9.8)

= 5.81 kg

so, its true weight = m*g

= 5.81*9.8

= 56.93 N

B) W_apparent = W_true + m*a

W_apparanet = m*g + m*a

36 = 56.93 + m*a

==> a = (36 - 56.93)/m

= (36 - 56.93)/5.81

= -3.6 m/s^2

C) W_apparent = m*g + m*a

= m*g + m*(-g)

= 0 N

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