Part A If air resistance is negligibly small, find the magnitude of the force th

Question

Part A If air resistance is negligibly small, find the magnitude of the force that this magnetic field exerts on the ball just as it enters the field. Use 1.602x10-19 C for the magnitude of the charge on an electron. A ball with a mass of 110 g which contains 4.30x108 excess electrons is dropped into a vertical shaft with a height of 140 m. At the bottom of the shaft, the ball suddenly enters a uniform horizontal magnetic field that has a magnitude of 0.300 T and direction from east to west. F- Submit Previous Answers Request Answer Incorrect; Try Again; 5 attempts remaining Part B Find the direction of the force that this magnetic field exerts on the ball just as it enters the field from north to south 0 from south to north Submit Request Answer

Explanation / Answer

magnitude of charge on the ball, q = N*e

= 4.3*10^8*1.6*10^-19

= 6.88*10^-11 C

B = 0.3 T

speed of the ball when it reaches the bottom of the shaft,

v = sqrt(2*g*h)

= sqrt(2*9.8*140)

= 52.4 m/s

A) magnetic force acting on the ball,

F = q*v*B*sin(theta)

= 6.88*10^-11*52.4*0.3*sin(90)

= 1.08*10^-9 N

B) From south to north

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