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Part A If a muon is traveling at 70% of the speed of light, how long does it tak

ID: 1949940 • Letter: P

Question

Part A
If a muon is traveling at 70% of the speed of light, how long does it take to decay in the observer's rest frame (i.e., what is the observed lifetime of the muon)?
Part B
If a muon is traveling at 99.9% the speed of light, how long will it take to decay in the observer's rest frame (i.e., what is the observed lifetime of the muon)?
Part C
Suppose that a cosmic-ray proton crashes into a nitrogen molecule in the upper atmosphere, 45 km above the earth's surface, producing a pion that decays into a muon. Assume that the muon has a downward velocity of 99.9943% the speed of light.
How far would the muon travel before it decayed, if there were no time dilation?
Part D
Now, let us consider the effects of time dilation. How far would the muon travel, taking time dilation into account?

I'm sorry that this is such a long problem. I will give Lifesaver if you please help!!!!




Explanation / Answer

(a)    =   2.2*10^-6 s velocity    v    = 0.7 * c    ==>   v /c =   0.7 according to relativity time deliation '     =   / sqrt ( 1 - (v/c)2)       =   3.081*10-6 s (b) if velocity of moun   v = 0.999 * c ==> v/ c =   0.999 '     =   / sqrt ( 1 - (v/c)2)       =   49.20*10-6 s ----------------------------------- (c) If there were no time delaiation effect life time of the moun =   2.2*10^-6 s velocity of the moun v   =   0.999943*c =   0.999943*3*10^8 m/s   =  2.999829*10^8 m/s distance travelled by the moun d   =   velocity * time =    2.999829*10^8 m/s )( 2.2*10^-6 s ) = 6.5996238*10^2 m ------------------------------------ (d) According to time delation v = 0.999943*c    ==> v / c =   0.999943 '     =   / sqrt ( 1 - (v/c)2)     = 206. 05*10^-6 s d   =   velocity * time =  (  2.999829*10^8 m/s )( 206.05*10^-6 s ) = 618.11476545*10^2 m '     =   / sqrt ( 1 - (v/c)2)       =   49.20*10-6 s ----------------------------------- (c) If there were no time delaiation effect life time of the moun =   2.2*10^-6 s velocity of the moun v   =   0.999943*c =   0.999943*3*10^8 m/s   =  2.999829*10^8 m/s distance travelled by the moun d   =   velocity * time =    2.999829*10^8 m/s )( 2.2*10^-6 s ) = 6.5996238*10^2 m ------------------------------------ (d) According to time delation v = 0.999943*c    ==> v / c =   0.999943 '     =   / sqrt ( 1 - (v/c)2)     = 206. 05*10^-6 s d   =   velocity * time =  (  2.999829*10^8 m/s )( 206.05*10^-6 s ) = 618.11476545*10^2 m