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Please help. Also please show all steps with explanation. Consider the three cap

ID: 1356280 • Letter: P

Question

Please help. Also please show all steps with explanation.

Consider the three capacitors connected as shown. A potential difference of V_ac = 120 V_is maintained between points a and c. What is the equivalent capacitance between points a and c? What is the value of the ratio V_bc/V_ab ? (Here V_bc and V_ab are, respectively, the values of the potential difference between b and c, and between a and b.) What is the potential difference V_bc across the 2.0 mu F capacitor? How much electric energy is stored in the 6.0 mu F capacitor ? What is the charge on the 4.0 mu F capacitor ?

Explanation / Answer

here,

Vac = 120 V

(a)

the equivalent capacitance of the circuit is , Ceq = (6 + 4) *2/(6 + 4 + 2)

Ceq = 1.67 uF

the equivalent capacitance of the circuit is 1.67 uF

(b) as ab and bc are in series

the ratio of Vbc /Vab = Cab/Cbc

Vbc / Vab = (6 + 4) /2

Vbc / Vab = 5

the ratio Vbc/Vab is 5

(c)

the potential difference , Vbc = Vac * Cab/(Cab + Cbc)

Vbc = 100 V

the potential difference Vbc is 100 V

(d)


Vab = 120 - Vbc

Vab = 20 V

the electric energy stored in 6 uF, TE = 0.5 * C*V^2

TE = 0.5 * 6 * 10^-6 * 20^2

TE = 0.0012 J

the electric energy stored in 6 uf capacitor is 0.0012 J