Part A Determine the coefficient of restitution between the truck and car.(Figur

Question

Part A

Determine the coefficient of restitution between the truck and car.(Figure 1)

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Part B

Determine the loss of energy due to the collision.

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The 4.0 Mg truck and 2.0 Mg car are traveling with the free-rolling velocities shown just before they collide. After the collision, the car moves with a velocity of 12 km/h to the right relative to the truck.

Part A

Determine the coefficient of restitution between the truck and car.(Figure 1)

e =

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Part B

Determine the loss of energy due to the collision.

?E =   kJ  

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Explanation / Answer

a)

e= final relative velocity /initial relative velocity

= 12/(30-10) = 0.6

B)

final velocity of truck = v

car = v+ 112 Km/h

4*30 + 2*10 = 4*v + 2*(v+ 12)

v= 19.3 Km/h

loss of energy = initial kinetic energy - final kinetic energy

= 0.5*(4x103)*302 + 0.5*(2x103)*102 - 0.5*(4x103)*19.32 + 0.5*(2x103)*31.32

= 170666.6Kg-Km2/h2

= 13.2x103 J

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