Please solve and explain: Two converging lenses are placed facing each other and

Question

Please solve and explain:

Two converging lenses are placed facing each other and 600 mm apart, with lens 1 to the left of lens 2. An object is placed 600mm to the left of lens 1, which has a focal length of 120mm .

Part A

If the focal length of lens 2 is 200 mm, what is the image distance measured relative to lens 2?

Express your answer with the appropriate units. Follow the sign convention.

Part B

What is the overall magnification of the image?

Follow the sign convention.

Part C

Is the image upright or inverted?

Please solve and explain: Two converging lenses are placed facing each other and 600 mm apart, with lens 1 to the left of lens 2. An object is placed 600mm to the left of lens 1, which has a focal length of 120mm . Part A If the focal length of lens 2 is 200 mm, what is the image distance measured relative to lens 2? Express your answer with the appropriate units. Follow the sign convention. Part B What is the overall magnification of the image? Follow the sign convention. Part C Is the image upright or inverted?

Explanation / Answer

1/s1 + 1/s1' = 1/f1

1/600 + 1/s1' = 1/120

s1' = 150 mm

m1 = -s1'/s1 = -150/600 = -1/4

for lens 2

s2 = 600-150 = 450 mm

1/s2 + 1/s2' = 1/f2

1/450 + 1/s2' = 1/200

s2' = 360 mm   <---------answer

m2 = -s2'/s2 = -360/450 = -4/5
image distance is 360 mmm to the right of the second lens

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part B)

M = m1*m2 = +1/5 = +0.2

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part c) upright

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