The diagram represents a snapshot of a standing transverse wave on a flexible st
ID: 1386210 • Letter: T
Question
The diagram represents a snapshot of a standing transverse wave on a flexible string taken when the displacement is at a maximum. The string is 1.28 m long with tension 5.00 N. The total mass of the string is 7.09 g.
Find the period of the oscillation.
Please Help!
The diagram represents a snapshot of a standing transverse wave on a flexible string taken when the displacement is at a maximum. The string is 1.28 m long with tension 5.00 N. The total mass of the string is 7.09 g.
Find the period of the oscillation.
Please Help!
Explanation / Answer
since the diagram is not visible so,
let there are n waves so
? = L / n
? = 1.28 / n
The speed of propagation of a wave in a string (v) is proportional to the square root of the tension of the string (T) and inversely proportional to the square root of the linear mass (?) of the string:
v = sqrt(?/?)
also
f = v/?
so,
f = sqrt(?/?) / ?
f = sqrt(5 / (0.007 / 1.28)) / (1.28 / n )
period ? = 1 / f
period = (1.28 / n ) / 30.2372
time period = 0.042332 / n (put the value of n according to the diagram)