Particles of charge +65, +48, and 95 C are placed in a line . The center one is
ID: 1405236 • Letter: P
Question
Particles of charge +65, +48, and 95 C are placed in a line . The center one is L = 60 cm from each of the others.
A)
Calculate the net force on the left charge due to the other two. Enter a positive value if the force is directed to the right and a negative value if the force is directed to the left.
B)
Calculate the net force on the center charge due to the other two. Enter a positive value if the force is directed to the right and a negative value if the force is directed to the left.
C)
Calculate the net force on the right charge due to the other two. Enter a positive value if the force is directed to the right and a negative value if the force is directed to the left.
Explanation / Answer
here,
charge Q1 = 65 uC
Q1 = 65 * 10^-6 C
Q2 = 48 * 10^-6 C
Q3 = - 95 uC
Q3 = -95 * 10^-6 C
L = 60 cm
L = 0.6 m
A)
net force on the charge Q1 , f = k * Q1 * Q3/1.2^2 - k * Q1 * Q2/0.6^2
f = 9*10^9 * 65 * 10^-6 * 95 * 10^-6/1.2^2 - 9 * 10^9 * 48 * 10^-6*65 * 10^-6/0.6^2
f = - 39.41 N
the net force on the left charge due to the other two is - 39.41 N
B)
net force on the charge Q2 , f = k * Q2 * Q3/1.2^2 + k * Q1 * Q2/0.6^2
f = 9*10^9 * 48 * 10^-6 * 95 * 10^-6/0.6^2 + 9 * 10^9 * 48 * 10^-6*65 * 10^-6/0.6^2
f = 192 N
the net force on the centre charge due to the other two is 192 N
C)
net force on the charge Q3 , f = - k * Q2 * Q3/1.2^2 - k * Q1 * Q3/0.6^2
f = - 9*10^9 * 48 * 10^-6 * 95 * 10^-6/0.6^2 - 9 * 10^9 * 65 * 10^-6*95 * 10^-6/1.2^2
f = -152.59 N
the net force on the right charge due to the other two is -152.59 N