Particles of charge +65, +48, and 95 C are placed in a line (Figure 1) . The cen
ID: 1496160 • Letter: P
Question
Particles of charge +65, +48, and 95 C are placed in a line (Figure 1) . The center one is L = 50 cm from each of the others.
Part A
Calculate the net force on the left charge due to the other two. Enter a positive value if the force is directed to the right and a negative value if the force is directed to the left.F+65 =
Part B
Calculate the net force on the center charge due to the other two. Enter a positive value if the force is directed to the right and a negative value if the force is directed to the left F48=
Part C
Calculate the net force on the right charge due to the other two. Enter a positive value if the force is directed to the right and a negative value if the force is directed to the left. F-95=
Explanation / Answer
q1 = +65 C
q2 = +48 C
q3 = - 95 C
L = 0.5 m
Force btw two charge particle is given by, F =k*q1q2/r^2
(A)
Net Force on the Left charge,
Fnet = k* [q1q3/r1^2 - q1q3/r2^2]
Fnet = 9.0*10^9 * 10^-12 * [(65*98)/1^2 - (65*48)/0.5^2 ]
Fnet = - 55.0 N
(B)
Net Force on the Middle charge,
Fnet = k* [q1q2/r1^2 + q2q3/r2^2]
Fnet = 9.0*10^9 * 10^-12 * [(65*48)/0.5^2 + (95*48)/0.5^2 ]
Fnet = 276.5 N
(C)
Net Force on the Right charge,
Fnet = k* [- q1q3/r1^2 - q2q3/r2^2]
Fnet = - 9.0*10^9 * 10^-12 * [(65*95)/1.0^2 + (95*48)/0.5^2 ]
Fnet = - 219.7 N