Please answer question 9 alpha particle (m = 4.002602 u) (3728 MeV/c^2) Consider
ID: 1410028 • Letter: P
Question
Please answer question 9 alpha particle (m = 4.002602 u) (3728 MeV/c^2) Consider the nucleus of gold-197 with an atomic mass of 196.966552 u. What is its atomic number? (79) How many neutrons does it have? (118) If you were to add up the mass of all 197 individual protons and neutrons that make up the nucleus, how much mass would they have (separately)? Answer in atomic mass units (198.640645 u) What is that mass in kilograms? (3.29 times 10^-25 kg) How much mass is lost when the individual protons and neutrons combine to make the gold nucleus? (1.674093 u) What is the binding energy of this nucleus? (1559 MeV) What is the binding energy per nucleon? (7.914 or 7.916 MeV/nucleon) Consider a nucleus of chromium-52 with an atomic mass of 51.940512 u. Find the mass defect. (0.489908 u) Find the binding energy per nucleon of this nucleus. (8.776 MeV/nucleon)
Explanation / Answer
a) Atomic number= 79
b) Neutrons= 118
c)
mp= 79* 1,00728=79,57512
mn=118*1,00866=119,02188
Ms=mp+mn= 198,597
d)Ms= 198,597*1,66054*10^-27=3,188*10 ^-25
e)Mass loss= Ms-M= 198,597 - 196,966552= 1,63 u
f) E=Mass loss* c^2=1,63* 931,494 (MeV/c^2)*c^2= 1490,3 Mev