Class Management I Help Chapter 3 Begin Date: 5/24/2016 12:00:00 AM Due Date: 5/

Question

Class Management I Help Chapter 3 Begin Date: 5/24/2016 12:00:00 AM Due Date: 5/28/2016 1:00:00 AM End Date: 5131/2016 12:00:00 AM (10%) Problem 8: An athlete crosses a 21 m wide river by swimming perpendicular to the water current at a speed of 0.45 m/s relative to the water. He reaches the opposite side at a distance 39 m downstream from his starting point. Randomized Variables w 21 m 39 m vs 0.45 m/s i A 50% Part (a) How fast is the water in the river flowing with respect to the ground in m/s? 4 50% Part (b) What is the speed of the swimmer with respect to a friend at rest on the ground in m/s? Grade Sun Submissio Attempts acos0 cotano asino atan0 acotano sinho cosh0 tanh0 cotanh0 ODegrees Radians I give up! Hint Submit Feedback: 5% deduction per feedback. Hints: 4% deduction per hint. Hints remaining: 2. All contest 2016 Bxpert

Explanation / Answer

a)

time taken = 21/0.45 = 46.67 sec ,

speed of river = 39/46.67

= 0.8357 m/s

b)

speed of swimmer with respect to friend

= sqrt( 0.45^2 + 0.8357^2)

= 0.9492 m/s

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