Class Management I Help Chapter 23B Begin Date: 4/2/2017 12:00:00 AM Due Date: 4
ID: 1623364 • Letter: C
Question
Class Management I Help Chapter 23B Begin Date: 4/2/2017 12:00:00 AM Due Date: 4/9/2017 11:59:00 PM End Date: 5/22/2017 12:00:00 AM (7%) Problem 2: In a simple AC circuit shown on the right, L 0.085 H and 4V 4V. sin aut), where 4V 15 V and w 21 rad/s Randomized Variables L 0.085 H 4V. 15 V 21 rad/s AV Otheexpertta.com 10% Part (a) Express the inductive reactance, XL, in terms of L, and a. 10% Part (b) Calculate the numerical value of X,,in ohms 10% Part (c) Express the current I as a function of time in terms of 4vmar and X 10% Part (d) Express the maximum of the current, in terms of 4vmar and X 10% Part (e) Calculate the numerical value of I in amps 10% Part (f If the current I reaches Imar at t 2.0 s, when will the closest V. appear after this time in the circuit? Grade Summary max 0.075 V, Deductions Potential 100% Late Work 80% cos0 Late Potential 80% 7 8 9 HOME sino tan N 4 5 6 cotano asino acos0 Submissions Attempts remaining: 1 atan0 acotan0 sinh0 (0% per attempt cosh0 tanh cotanh0 detailed view vo Degrees Radians BACKSPACE DEL CLEAR Submit Hint I give up! Hints 1 for a 0% deduction. Hints remaining: Feedback 0% deduction per feedback. The phase of Vis Ju/2 earlier than the phase of I.Explanation / Answer
Given that ; L = 0.085 H, Delta v = 15 V, omega w = 21 rad/s
(a) the inductive reactrance is
X_L = w×L
(b) The numerical value of X_L is
X_L = 21 × 0.085
= 1.785 ohm
(c) the current I is
I = (E0/w×L) sin(wt - pi/2)
(d) the maximum of the current Imax is
Imax = Vmax/X_L
(e) Imax = 15/1.785
= 8.403 A
(f) the current in the circuit legs voltage by pi/2.
the current reaches its maximum value Imax when the V completed quarter of the cycle.
wt = pi/2
t = 3.14/2×21
= 0.0747 s