Please answer the 3 questions listed below: Distance Time Average Velocity Final
ID: 1416955 • Letter: P
Question
Please answer the 3 questions listed below:
Distance
Time
Average Velocity
Final Velocity
Acceleration
How does the (Average) calculated values in the table compare to the known value of g?
Why is Vave multiplied by 2 to obtain Vf?
The acceleration due to gravity is what value?
Trial NumberDistance
metersTime
secondsAverage Velocity
m/sFinal Velocity
2 x VaveAcceleration
Vf / t 1 1 0.45 2.22 4.44 9.9 2 1.5 0.55 2.73 5.45 9.91 3 2 0.63 3.17 6.35 10.07 4 2.5 0.71 3.52 7.04 9.918 5 3 0.78 3.84 7.7 9.862 6 3.5 0.84 4.17 8.33 9.921 7 4 0.9 4.44 8.9 9.876 8 4.5 0.95 4.74 9.5 9.973 9 5 1.01 4.95 9.9 9.802 10 5.5 1.05 5.24 10.5 9.977 11 6 1.1 5.45 10.91 9.918 Average 3.5 0.815 4.04 8.087 9.919Explanation / Answer
velocity average is the sum of intail and final divided by two
so Vavg = (Vi+ Vf)/2
if Vi = 0
Vf = 2 Vavg
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from table avg accleration = (9.9+9.91 + 10.07 + 9.918 + 9.862 + 9.921 + 9.876 + 9.973 + 9.802 + 9.977 + 9.918 + 9.919)/10
avag = 9.919 m/s^2
g is 9.8 m/s^2
% difference = ( 9.918 - 9.81)/9.81 *100
% difference = 1.2 %
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The acceleration due to gravity is what value is 9.8 m/s^2