If anyone can help with this, it would be greatly appreciated. Please do all sec
ID: 1420129 • Letter: I
Question
If anyone can help with this, it would be greatly appreciated. Please do all sections. Thank you!
Two masses are attached by a massless cord on a pulley M_p = Mass of pulley R_p = radius of pulley I = Moment of inertia at point of rotation of pulley The surface is frictionless with respect to angle theta. (Tension are not equal) Write an equation to solve for the linear acceleration of M_1. Write an equation to solve for the linear acceleration of M_2. Write an equation to solve for the angular acceleration of M_p. Write an equation to solve for the linear acceleration of the system. Solve in terms of M_1, M_2, M_p, R_p, theta, I.Explanation / Answer
a) Let tension on the string close to m2 be T2 and on the other part be T1
From newtons second law
m1*g*sin(theta) + T1 = m1*a
b)
m2*g - T2 = m2*a
c)
(T2 - T1)*Rp = Ip*a/Rp
d) adding all
m1*g*sin(theta) + T1 + m2*g - T2 + T2 - T1 = ma*a + m2*a + Ip*a/Rp^2
a = [m1*sin(theta) + m2]g/[m1 + m2 + Ip/Rp^2]