Block A, with mass mx, is initially at rest on a horizontal floor. Block B, with
ID: 1422824 • Letter: B
Question
Block A, with mass mx, is initially at rest on a horizontal floor. Block B, with mass m_B, is initially at rest on the horizontal to surface of A. The coefficient of static friction between the two blocks is Block A is pulled with an increasing force. It begins to slide out from under B when its acceleration reaches: mug mgmug g (m_a/m_a)mu,g (mg/m_A)mu_1g Block A. with a mass of 16 kg. rcsis on a 25degree incline The coefficient of kinetic friction is mu_g 0.4. An attached rope is parallel to the incline and passes over a massless. frictionless pulley at the top of the plane. Block B with a mass of 5 kg. is attached to the dangling end of the rope. What is the acceleration of block B?Explanation / Answer
(1) answer is usg
when acceleration reaches this value it will start to slide from surface B.
(2) Now let us consider the tension in the string is T
Write the equation of motion for block 16 kg
MgSin(25) = uMgCos(25) + T +Ma
where M is mass = 16 kg and a is acceleration
T = MgSin(25) - uMgCos(25) -Ma ---------(1)
Now for block 5 kg
T = mg +ma -------(2)
Equating 1 and 2
therefore
a = -1.886 m/s2
-Ve means direction is opposite then assumed