Pictured in the figure below. A = 11-cm length of conductor of mass 29 g, free t
ID: 1428116 • Letter: P
Question
Pictured in the figure below. A = 11-cm length of conductor of mass 29 g, free to move vertically, is placed between two thin, vertical conductors, and a uniform magnetic field acts perpendicular to the page. When a 5.0-A current is directed as shown in the figure, the horizontal wire moves upward at constant velocity in the presence of gravity. What forces act on the horizontal wire, and under what condition is the wire able to move upward at constant velocity? Find the magnitude and direction of the minimum magnetic field required to move the wire at constant speed. What happens if the magnetic field exceeds this minimum value? (The wire slides without friction on the two vertical conductors.)Explanation / Answer
Here,
l = 0.11 m
mass , m = 0.029 Kg
current , I = 5 A
a)
the forces on the wire are : gravity force and magnetic force
for wire to move with constant velocity
gravity force should be equal and oposite to the magnetic force
b)
for zero acceleration
B * i * l = m * g
B * 0.11 * 5 = 0.029 * 9.8
solving for B
B = 0.517 T
for the force to be upwards
the magnetic field must be out of the page
the magnetic field must be 0.517 T and direction will out of the page.
c)
when the magnetic field is higher than the minimum field.
the magnetic force will be higher than the gravity
and the wire will accelerate in upwards direction