Please solve 978. Thankyou one shown in Problem 974.) 976 A parallel beam of lin
ID: 1428848 • Letter: P
Question
Please solve 978. Thankyou
one shown in Problem 974.) 976 A parallel beam of linearly polarized light of wavelength 589 nm (in vacuum) is incident on a calcite crystal. The propagation direction is perpendicular to the optic axis. (a) Find the wavelength of the ordinary and extraordinary wave in the crystal (b) Find the minimm thickness of crystal n (b) Find the minimum thickness of crystal necessary to produce phase differences of /4 radians, /2 radians, and radians between the emergent waves. (c) If the E vector in the incident light makes angle 45° with the optic axis, what is the state of polarization of the emergent light in the three cases in part (b)? 977 A sheet of cellophane is a half-wave retardation plate for 400 nm light. Neglect variation of n with (dispersion) in the cellophane -1 (a) How does the sheet behave for 800 nm light ? (b) White light is incident on the sheet with E vector at 45° to the optic axis (1inearly polarized). If the light emerging from the cellophane is examined with a polaroid disk oriented the same as the initial polarizer, what part of the visible spectrun will be transmitted through the second polarizer ? g from S passes through polarizer P1, which can Ys P, which can Ys 978 In the diagram, 11g ht coming f rotate around the Y axis, into a scattering medium, and is scattered along the -X axis through polaroid P2, which can rotate around the X axis. The eye observes the lightExplanation / Answer
978
a)
as the output is given as
Iout = Iin * cos(theta)^2
for maximum brightness , theta = 0 degree
Now, after rotating 90 degree
theta = 90 degree
Iout = Iin * cos(90)^2
as cos(90) = 0
yes, the observer will see the dark
b)
Now , theta = 90 - 90 = 0 degree
as theta = 0 degree
cos(0) = 1
the observer will see bright
c)
theta = 0 + 90 = 90 degree
Iout = Iin * cos(90)^2
as cos(90) = 0
the observer will see dark