Part A ± Gravitational Force of Three Identical Masses What is the magnitude of

Question

Part A ± Gravitational Force of Three Identical Masses What is the magnitude of the net gravitational force Fgav on the mass at the origin due to the other two masses? Three identic al very dense masses of 6700 kg each are placed on the x axis. One mass is at z Take the gravitational constant to be G 667 10-11 N m2/kg Take the gravitational constant to be G-6 67x10-11 N·m Express your answer in newtons to three significant figures. -120 cm , one is at the origin, and one is at 360 cm grav Submit Hints MYAnswers Give Up Review Part

Explanation / Answer

r1 = distance of mass on left from mass on center = 120 cm = 1.20 m

r2 = distance of mass on right from mass on center = 360 cm = 3.60 m

m = mass = 6700 kg

F1 = Gravitational force by mass on left on mass at origin   towards left

F2 = Gravitational force by mass on right on mass at origin      towards right

Since the force are opposite

Net force = F1 - F2

Net force = Gm2/r21 - Gm2/r22 =    G m2 [1/r12 - 1/r22] = (6.67 x 10-11) (6700)2 [1/(1.20)2 - 1/(3.60)2]

Net force = 0.00185 N

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