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Please help and show your work to the following problem! Thanks :) Problem 3 Con

ID: 1436141 • Letter: P

Question

Please help and show your work to the following problem! Thanks :)

Problem 3 Consider the circuit of three identical batteries and three identical bulbs connected exactly as shown here. In this problem, assume that each battery is a perfect physics battery supplying voltage V and the bulbs are perfect ohmic devices with resistance R. A friend of yours says, "That middle battery is hooked up backwards! The bulbs won't light if you hook the circuit up like that (a) Respectfully and thoroughly explain to your friend that the bulbs will indeed light. b) Find the voltage drop across each resistor. (c) Find the power dissipated by each bulb and the total power dissipated by the circui

Explanation / Answer

a) if they were connected forward, the total voltage supplied by battery would be V+V+V = 3V

Now since one battery is connected backward, total voltage supplied = V -V +V = V

Total resistance = R+R+R=3R

Since still the total voltage supplied is V which is not equal to zero, so current will flow in the circuit and hence all bulbs will light up

b) by ohms law, current i = V/3R

voltage drop across each register = iR = R* V/3R = V/3

C) POWER dissipated across each redistor = i2 R = (V/3R)2*R = V2 /9R

Total power dissipated = 3*V2 /9R = V2 /3R