Problem 19.46 A 0.50-F and a 1.4-F capacitor (C1 and C2, respectively) are conne

Question

Problem 19.46 A 0.50-F and a 1.4-F capacitor (C1 and C2, respectively) are connected in series to a 11-V battery. Part A Calculate the potential difference across each capacitor. Express your answers using two significant figures separated by a comma. Part B Calculate the charge on each capasitor. Express your answers using two significant figures separated by a comma. Part C Calculate the potential difference across each capacitor assuming the two capacitors are in parallel. Express your answers using two significant figures separated by a comma. Part D Calculate the charge on each capasitor assuming the two capacitors are in parallel. Express your answers using two significant figures separated by a comma.

Explanation / Answer

part A )

when they are in series

Ceq = 0.50 * 1.4 / ( 0.5 + 1.4)

Ceq = 0.368 micro F

Q = Ceq * V = 4.05 x 10^-6 C

in series charge remain same on every capacitor

V1 = Q/C1 = 8.105 V

V2 = Q/C2 = 2.895 V

V1 , V2 = 8.1 , 2.9

part B )

Q1 = Q2 = 4.1 x 10^-6 C , 4.1 x 10^-6 C

part c )

if they are in parallel then they both are on same potential

V1 = V2 = 11V , 11V

part d )

Q1 = V*C1 = 5.5 x 10^-6 C

Q2 = V*C2 = 1.54 x 10^-5 C

Q1 , Q2 = 5.5 x 10^-6 , 1.5 x 10^-5

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