Problem 19.46 A 0.50- F and a 1.4- F capacitor ( C 1 and C 2, respectively) are
ID: 1589734 • Letter: P
Question
Problem 19.46
A 0.50-F and a 1.4-F capacitor (C1 and C2, respectively) are connected in series to a 21-V battery.
Part A
Calculate the potential difference across each capacitor.
Express your answers using two significant figures separated by a comma. Units in V.
Part B
Calculate the charge on each capasitor.
Express your answers using two significant figures separated by a comma. Units in C.
Part C
Calculate the potential difference across each capacitor assuming the two capacitors are in parallel.
Express your answers using two significant figures separated by a comma. Units in V.
Part D
Calculate the charge on each capasitor assuming the two capacitors are in parallel.
Express your answers using two significant figures separated by a comma. Units in C.
Explanation / Answer
given are
C1=0.50uF
C2=1.4uF
V=21V
1/Ceq=1/c1+1/c2
=1/0.50+1/1.4
Ceq=0.370uF
Q=Ceq V
=0.370*21
=7.77uC
In series charge will remain same
Q1=Q2=7.77uC—answer b
Delta V1=Q1/V1=7.77*10^-6/0.504
Delta v1=15.4 V—answer a
Delta V2=Q2/V2=7.77*10^-6/1.4*10^-6
Delta v2=5.55V—answer a
c)in parallel they have same voltage
V1=v2=21V—answer c
d)Q1=C1V1
=0.50*21
Q1=10.5uC—answer d
Q2=C2v2
=1.4*21
Q2=29.4uC---answer d