Please I need help with this. Note it is multiple parts. Thanks (27%) Problem 7:
ID: 1437801 • Letter: P
Question
Please I need help with this. Note it is multiple parts. Thanks (27%) Problem 7: In the coordinate system shown at right, particle 1 with charge qu q, where q 6.4 uc, is located at coordinates (-a,0) m, where a 4.2 m; 3 (0, a) particle 2 with charge q2 24 is located at coordinates (a,00 particle 3 with charge q is located at coordinates (0,a) 2 (a, 0) 1 (-a, 0) Otheexpertta.com 14% Part (a) Find the electric potential at the origin Vo; express it using the symbols given. 14% Part (b) Solve for the numerical value of Vo in JC. 814% Part (c) Using a to denote the direction of the clectric field at the origin Eo, measured counterclockwise from the positive x-axis, find tan(a) A 14% Part (d) Now find sin(a). 14% Part (e) Solve for the numerical value of a. (Suppose a is between 0 and 360°) iil 14% Part (0 Select the correct equation for the magnitude of the electric field Eo at the origin in terms of symbols given 14% Part (g Solve for the numerical value for the magnitude of Eoin NIC. Grade Summary Deductions 0% Potential 100% Submissions sino cos0 tan0 1t 7 8 9 Attempts remaining: 5 cotano asino acoso 4 5 6 per attempt detailed view 1 2 3 atano acotano sinh0 cosh0 tanh00 cotanhoExplanation / Answer
q1 = q
q2 = 2*q
q3 = q
a = 4.2 m
q = 6.4 uC
(c)
Effect of charge q1 will be cancelled by q2, So net Electric field at origin will be only becoz of leftover charge q2 & q3.
Direction of Electric Field at Origin, = 180 + 45
Direction of Electric Field at Origin, = 225o
(d)
sin() = sin(225) = - 0.707
(e)
tan() = tan(225) = 1.
(f)
Eo = - k*q2/a^2 i^ - k*q3/a^2 j^
(g)
Eo = - (8.9*6.4)/4.2^2 i^ - (8.9*6.4)/4.2^2 j^
Eo = - 3.23 i^ - 3.23 j^
|Eo| = sqrt(3.23^2 + 3.23^2)
|Eo| = 4.57 N/C