Disk #1 m1= 4.0kg u1= 2.40 m/s 1= 30 Disk #2: m2= 4.0kg u2= 2.80 m/s 2= 25.5 1.F
ID: 1441575 • Letter: D
Question
Disk #1
m1= 4.0kg
u1= 2.40 m/s
1= 30
Disk #2:
m2= 4.0kg
u2= 2.80 m/s
2= 25.5
1.Find the components of the momentum of each disk that are parallel and perpendicular to the axis defined by the motion of the center of mass of the system prior to the collision, that is, find 1p,1p,2p and 2p, where the symbols and refer to motion that is parallel and perpendicular to the axis defined by the motion of the center of mass of the system prior to the collision
2A. Find the total and components of the momentum.
2B. Find the velocity of the center of mass of the system (magnitude and direction).
Explanation / Answer
1.
1_parallel = m1u1cos30 = 4 x 2.40 x cos30 = 8.31 kg m/s
1_perpendicular = m1u1sin30 = 4 x 2.40 x sin30 = 4.8 kg m/s
2_parallel = m2u2cos25.5= 4 x 2.80 x cos25.5 = 10.11 kg m/s
2_perpendicular = m2u2sin25.5 = 4 x 2.80 x sin25.5 = 4.82 kg m/s
2A. component
parallel = 8.31 + 10.11 = 18.42 kg m/s
perpendicular = 4.8 + 4.8 = 9.6 kg m/s
total momentum = sqrt(18.42^2 + 9.6^2) = 20.78 kg m/s
direction = tan^-1(9.6/18.42) = 27.6 deg
2B. Vcm = total momentum / total mass = 20.78 / (4+4) = 2.60 m/s
direction will be same as momentum - 27,6 deg