Reminder : No collision is truly elastic! In procedure 3: assume cart 1 has mass

Question

Reminder: No collision is truly elastic!

In procedure 3: assume cart 1 has mass 250 g and initial velocity +v10 = 2.03 m/s, and cart 2 has mass 885 g. Assume the track is frictionless, and after the "elastic" collision cart 1 is moving at v1 = -1.096 m/s and cart 2 is moving at v2 = 0.873 m/s.

a) What percentage of the original energy was lost in this collision?
___________ %

b) What percentage of the original linear momentum was "lost" due to external forces? (Remember: linear momentum is a vector!)
p = ______%

Explanation / Answer

KE_1=0.52

FINAL k.e_2=0.15'+0.34

total ke=0.49

loss energy percent=5.76

initial momentum=0.54

final=.25*-1.096+0.885*.873=0.49

loss %=9.25

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