Consider the system shown in Figure 3. A uniform meter stick with the center of
ID: 1454978 • Letter: C
Question
Consider the system shown in Figure 3. A uniform meter stick with the center of mass at the 50 cm mark is pivoted at that point. If a mass of 50 g is hanging on the 20 cm mark, what is the torque applied by this mass on the meter stick please show your calculation. T = N.m The rotation is clockwise counter clockwise What mass should be hung at the 70 cm mark in order to balance the system please show your calculation M = g. Draw a free body diagram of the meter stick with all the forces exerted on it. When the system is in equilibrium, what is the total upward force exerted on the meter stick What is the total downward force on the meter stick Don't forget the meter stick has weight too.Explanation / Answer
Solution:
The total downward force = Total upward force since the meter stick is in equilibrium.
F douwnward = 12.25 N
The meterstick's mass is included in the balancing upward force.