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A rectanglular loop consists of 3 turns of wire carrying a current of 3.3 A. The

ID: 1467671 • Letter: A

Question

A rectanglular loop consists of 3 turns of wire carrying a current of 3.3 A. The loop is in the x-y plane, and the direction of flow of the current is shown in the figure. The loop has dimensions a = 1 cm and b = 6 cm. Consider a uniform magnetic field of strength 2.2×10-4 T in x, y, or z directions.

1)If the uniform field of 2.2×10-4 T is along the +x axis, find the magnitude of the torque acting on the loop and the total force on side a and b.

= __________N*m

Fa =__________N

Fb =__________N

2) If the uniform field of 2.2×10-4 T is along the +y axis, find the magnitude of the torque acting on the loop and the total force on side a and b.

= _________N*m

Fa =_________N

Fb =_________N

3) If the uniform field of 2.2×10-4 T is along the +z axis, find the magnitude of the torque acting on the loop and the total force on side a and b.

= _________N*m

Fa =_________N

Fb =_________N

Explanation / Answer

torque = magnetic field * current * number of turn * area * sin*(theta)

where theta is the angle between magnetic field and area vector

when magnetic field toward x axis

torque = magnetic field * current * number of turn * area * sin*(0)

torque = 0 Nm

force = magnetic field * current * length * sin(theta)

Fa = magnetic field * current * length * sin(0)

Fa = 0 N

Fb = magnetic field * current * length * sin(90)

Fb = 2.2 * 10^-4 * 3.3 * 0.06 * sin(90)

Fb = 0.00004356 N

when magnetic field toward y axis

torque = magnetic field * current * number of turn * area * sin*(0)

torque = 0 Nm

force = magnetic field * current * length * sin(theta)

Fa = magnetic field * current * length * sin(90)

Fa =  2.2 * 10^-4 * 3.3 * 0.01 * sin(90)

Fa = 0.00000726 N

Fb = magnetic field * current * length * sin(0)

Fb = 0 N