In the circuit shown in the figure (Figure 1) , the capacitors are all initially
ID: 1477076 • Letter: I
Question
In the circuit shown in the figure (Figure 1) , the capacitors are all initially uncharged and the battery has no appreciable internal resistance. Assume that E = 45.0V and R = 17.5 Omega .
A) After the switch S is closed, find the maximum charge on each capacitor.
q10,q20,q30,q40= ? pC
B)After the switch S is closed, find the maximum potential difference across each capacitor.
V10,V20,V30,V40 = ? V
C)After the switch S is closed, find the maximum reading of the ammeter A.
IA= ?
D)After the switch S is closed, find the time constant for the circuit.
t=?
Explanation / Answer
Effective capacitance is 1/C = 1/C1+1/C2+1/C3+1/C4
C = 4.8 pF
Now, Its a simple RC Circuit with R =17.5 ohms and C =4.8 pF
a)Total Charge is Q=CV = 216 pC
q10 = 21.6 pF,q20 =43.2 pF ,q30 = 64.8 pF,q40= 86.4 pF
c) Maximum Current is Q0/RC = V/R =45/17.5 = 2.57 A
d) Time constant RC = 84 pico seconds