Masses are balanced as shown on a 0.45 kg meter stick. What is the unknown mass

Question

Masses are balanced as shown on a 0.45 kg meter stick. What is the unknown mass m 1.081 kg 1.217 kg 1.097 kg 1.161 kg 0.9305 kg 0.9212 kg For the uniform steel beam shown, M = 2500_kg, m = 440_kg, R = 7.2_m/ and r = 1.3_m. Find the support force from beam B. _17170_N 18990_N 11400_N 20890_N 15780_N 24080_N Let vector A = -6.4i cap + 1.9j cap + 1.5k cap and B = B cap = 6i cap + 6.4J cap + 2.6j cap. Then find vector C = vector A x vector B. Cx -5.355 -5.798 -4.673 -4.66 -9 -7.858 Cy 25.64 25.57 34.13 28.58 23.78 37.77 Cg -88.54 -100.9 -56.36 -64.86 -52.36 -62.21

Explanation / Answer

1.

If the system is in equilibrium the net torque exerted in the system is zero.

(1.8)(9.8)(35-5)+(0.5)(9.8)(35-20)

= (0.45)(9.8)(50-35)+M(9.8)(80-35)

Hence the unknown mass is

M=1.217 kg

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