Masses - 125ML Flask = 63.46 ML 100ML Beaker = 31.80 ML Zinc Powder = 2.00g Iodi
ID: 487358 • Letter: M
Question
Masses -
125ML Flask = 63.46 ML
100ML Beaker = 31.80 ML
Zinc Powder = 2.00g
Iodine Crystals = 2.00g
Flask & Zinc = 64.85
Beaker & Product = 34.46
Questions: Final Mass of unreacted Zinc?, Mass of Zinc Reacted?, Mass of Iodine?, Moles of Zinc Metal Reacted?, Moles Iodine (I2) Reacted?, Moles I atoms reacted?, Ratio Moles Iodide Ion to Moles Zinc Ion?, Empirical Formula of Zinc Iodide?
These were all the numbers I have. We are doing experiment Synthesis of the Compound Zinc Iodide from its elements. The only reaction I see is the observation of how the mixture changed colors at it was boiling.
I have other question to answer also like... Calculate the total mass of Zinc and Iodine before the reaction?
Explanation / Answer
Zn(s) + I2(g) -- > ZnI2(s)
so...
mol of Zn = mass/MW = 2/65.38 = 0.03059
mol of I2= mass/MW = 2/253.808940 = 0.00787
ratio is 1:1 so I2 limits
0.00787 mol of I2 reacts...
0.00787 mol of Zn reacts
mol of I2 left = 0.00787-0.00787 = 0
mol of Zn left = 0.03059-0.00787 = 0.02272
mass of Zn left = 0.02272*65.38 = 1.4854 g of Zn left
mass of zinc reacted = 0.00787*65.38 = 0.5145 g of Zn reacted
Mass of iodine = 2 g reacted
ratio moles of Iodine to Zn --> 2 mol of I- per 1 mol of Zn+2 = 2:1 or 2