MasteringPhysics: Chapter Fifteen Google Chrome https gphy ext&i; Copy of Romash

Question

MasteringPhysics: Chapter Fifteen Google Chrome https gphy ext&i; Copy of Romashet 401 Sp15 Walker 4 Chapter Fifteen Item 20 Item 20 A person weighs 678 N in air but only 502 N when standing in water up to the Start Part A Find the volume of each of the person's legs. Submit My Answers Give Up Incorrect, Try Again Part B Find the mass of each leg, assuming they have a density that is 1.05 times the density of water kg m E Submit My Answers Give Up Signed in as Ahmed Amin Help close Resources previous l 20 of 22 l next Brodde Continue 8:33PM 12/9/2015

Explanation / Answer

weight of person in air= 678 N

weight of person in water= 502 N

buoyant force= loss i weigt= 678-502 = 176 N

V d g = 176 where v= volume of legs, d = density of water   

V(1000)(9.8) = 176

v(9800) = 176

V= 176/9800

V=0.018 m^3

(b) mass of legs= volume x density of legs

= 0.018 (1.05 x 1000) = 18.9 kg

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