I. Use the DNA sequence below, which encodes a prokaryoticgene to answer the fol

Question

I. Use the DNA sequence below, which encodes a prokaryoticgene to answer the following questions 21 71 121 31 81 131 41 ATGAGGAGTT GACACACAAG AGGAGGTAGC AGTATGGGTA TAATCTAATG 51 CGTAATTGAG GAGGTAGTTG ACGTATGAAT AGTTAACGTA CGGGGGGGAA 101 ACCCCCCCTT TTTTTTTTTC GAGCAATAAA AGGGTTACAG ATTGCATGCT 61 91 141 a) Write down the corresponding sequences, find them in the sequence above and label them (label as -35) -35 Consensus sequence -10 Consensus sequence (Pribnow box) Shine-Dalgarno sequence in corresponding mRNA Start (initiation) codon in corresponding mRNA Stop (termination) codon in corresponding mRNA (label as Pribnow) (label as SD) (label as start) (label as stop) b) Whatregion of this prokaryotic DNA sequence will be transcribed into mRNA? Circle one 1-131 71-119 74-149 54-119 c) What will the sequence be for the protein translated from this mRNA? d) Where is the 3'UTR? Circle one 9-131 41-119 81-141 87-119

Explanation / Answer

a.

- 35 consensus sequence = TTGACA ( 9 - 14 DNA region)

-10 concensus sequence (pribnow box) = TATAAT ( 39 - 44 DNA region)

Shine-Dalgarno sequence (SD) = AGGAGGT ( 21 - 27 DNA region),

Start codon = ATG ( 48 - 50 )

Since it is prokaryotic mRNA which is polycistronic therefore there may be numder of stop codon

Like TGA ( 57 - 59), TGA ( 69 - 71), TAA ( 84 - 86 )

b.

1 - 131

c.

Depends upon the Releasing Factors (RF1, RF2, ) and which stop codon is used ,the sequece of protien may be different. As the first stop codon (TGA) is present only nine bases apart from the initiation codon AUG, therefore the sequence of oligopeptide is;

Met - Arg - Asn

As there is no intercistronic region from which another peptide` shine- Dalgarno sequence will be recognised and niether there is second initiation codon to start.

d.

81 - 141

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