For the circuit shown in the figure, the current in the 8.0 ohm resistors is 0.5

Question

For the circuit shown in the figure, the current in the 8.0 ohm resistors is 0.50A. What is the current in the 2.0-ohm resistor? All the numbers shown are accurate to two significant figures. 9.5 A 6.4 A 2.25 A 4.5 A 0.75 A Three capacitors are arranged as shown in the figure, with a voltage source connected across the combination. C_1 has a capacitance of 9.0 pF, C_2 has a capacitance of 18.0 pF, and C_3 has a capacitance of 27.0 pF. Find the potential drop across the entire arrangement if the potential drop across C_2 is 257.0 V. 430 V 1000 V 470 V 1500 V

Explanation / Answer

A)

Voltage across 8 ohm resistor V(8) = Ri = 8(0.5) = 4V.
Current across 16 ohm resistor i(16) = V/R = 4/16 = 0.25A.
Current through the 20 ohm resistor, i(20) = i(8) + i(16) = 0.5 + 0.25 = 0.75A.
V(20) = iR = 0.75 * 20 = 15V.
Source voltage, Vs = V(8) + V(20) = 4 + 15 = 19V.

Current through 2 ohm resistor, i(2) = V/R = 19 / 2 = 9.5A

B)

Related Questions

Navigate

• Browse (All)
• Browse F
• Subjects

---