Please help!!!! The select section has the choices (above and below) Round your
ID: 1525060 • Letter: P
Question
Please help!!!!
The select section has the choices (above and below)
Round your final answers to three significant figures. Two tiny objects with equal charge of 4.7 mu C are placed at two corners of a square with sides of 0.723 m, as shown. Where would you place a third small object with the same charge so that the electric field is zero at the corner of the square labeled A? The change should be placed on a line that makes an angle of _____ degree the negative x-axis (choosing the origin to be at A) at a distance of _____ m along that line from point A.Explanation / Answer
Let a be the side of the square and q be each charge.
The field on A due to the charge in the left is kq/a^2 = E (say)
This is vertically up.
The field due the right charge on A is E/2.
Since the distance between A and this charge is (2) a
Its component horizontally (to the left) and vertically (up) is (2)* E/2 = (E/2)
Net field vertically up is (1+ (1/2) E
Net field horizontally to the left is (E/2)
The resultant of these is at angle from the x direction such that
tan = (1+ (1/2) / (1/2) or = 67.50º from the horizontal
The third charge is placed along this direction at a distance Na.
Its filed at A = E/N^2.
Equating its component in the horizontal direction
E/N^2.cos 67.50º = (E /2) which gives
N^2.cos 67.50º = 2
N = 1.92
x = Na cos 67.50º =1.92 *0.330* cos 67.50º = 0.24m
y = Na sin 67.50º = 1.92 *0.330* sin 67.50º = 0.59 m
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