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Tools Help yplus com/edugen/student/mainfruni Search Home /Login weey... U University of South AL. NEXT PRINTER VERSION The figure shows an arrangement of four charged particles, with angle e 39.0 and distance d 2.50 cm. Particle 2 has charge az 8.00 x 10 19 c; particies 3 and 4 have charges qa qa 1.60 x 10 19 C. (a) what is the distance D between the origin and partide 2 if the net electrostatic force on partide 1 due to the other partides is zero? (b) f particles 3 and 4 were moved doser to the x axis but maintained their symmetry about thvat axis, would the required value ofDbe greater than, less than, or the same as in part (a)? (a) Number (b) click if you would like to show work for this question: Modtushow. Mark une All Rights Reserved. A Civision ofExplanation / Answer
The force on q1 due to q3 and q4 will be along the lines joining the q3-1 and q4-q1 . the magnitude of the force will be same
we will resolve the forces alongthe x-axis and y-axis. the y-components will be opposite in direction and will cancel up where as the x-xomponents will add up
the net force on Q1 due to Q3 and Q4
= k*2* Q1*1.6e-19 /(2.52 +2.52tan230) magnitude only
This must be equal to the force due to Q2 on Q1 , so that th enet force on Q1 =0
= k*Q1*8.0e-19/(2.5+D)2
k*2* Q1*1.6e-19 /(2.52 +2.52tan230) = k*Q1*8.0e-19/(2.5+D)2
(2.5+D)2 = 4 * (2.52 +2.52tan230)
(2.5+D)Cos(30) = 5
D = 3.27 cm