Class Management Help Chapter 4 Begin Date: 2/15/2017 12:00:00 AM Due Date: 2/21

Question

Class Management Help Chapter 4 Begin Date: 2/15/2017 12:00:00 AM Due Date: 2/21/2017 11:00:00 AM End Date: 2/21/2017 00:00 PM (11%) Problem 9: A man is attempting to lift a crate using a two part pulley system as shown in the image. The crate has mass m2 62 kg, and the man has mi 75 kg. He pulls downward on the rope with a force of magnitude F 516 N. The pulleys are massless and frictionless. Otheexpertta.com A 25% Part (a) Using T to describe the magnitude of the tension force, write an expression for the sum of the forces in the y-direction acting on the crate in terms of gravity and the variables provided Grade Summary 0% Deductions Potential 100% 7 8 9 Submissions Attempts remaining: 5 4 5 6 04% per attempt detailed view 1 2 3 Submit Hint Feedback I give up! Hints 2% deduction per hint. Hints remaining: 3 Feedback 2% deduction per feedback. A 25% Part (b) Using the results from above, write an expression for the crate's vertical acceleration, a in terms of T. A 25% Part (c) What is the magnitude of the tension force, Tin newtons A 25% Part (d) What is the block's acceleration, a in m/s

Explanation / Answer

part a:

forces acting on the crate are:

1. tension in the middle rope=T

2. tension in the right rope=T

both in vertically upward direction

3. weight of the crate =m2*g

in vertically downward direction

force equation in y direction:

summation Fy=T+T-m2*g

part b:

vertical acceleration=(2*T-m*g)/m

=(2*T/m)-g

=(2T/62)-9.8=0.032258*T-9.8 m/s^2

part c:

T=F=516 N

part d:

ac=0.032258*516-9.8=6.8451 m/s^2

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