Class I Help HW 5 Magnetic Force Begin Date: 7/21/2018 4:00:00 AM - - Due Date:
ID: 306390 • Letter: C
Question
Class I Help HW 5 Magnetic Force Begin Date: 7/21/2018 4:00:00 AM - - Due Date: 7/23/2018 11:59:00 PM End Date: 7/23/2018 11:59:00 PM (1796) Problem 4: A negative charge of q =-9.5x 10-17C and m = 8.2 × 10-26 kg enters a magnetic field B-0.55 T with initial velocity v = 740 m/s, as shown in the figure. The magnetic field points into the screen. Randomized Variables 4--9.5 x 10-17c m - 8.2 x 10-26kg B 0.55 T v 740 m/s ©theexpertta.com 13% Part (a) which direction will the magnetic force be on the charge? Grade Summa OTo the right. Upward Downward. Out of the screen. 0% 100% Into the screen. OTo the left. Potential Attempts remaining: 5 0% per attempt) detailed view Submit Hint I give up! Hints: 496 deduction per hint. Hints remaining:- Feedback: 5% deduction per feedback. 13% Part (b) Express the magnitude of the magnetic force, F, in terms of qÝ, and B 13% Part (c) Calculate the magnitude of the force F, in newtons L 13% Part (d) Under such a magnetic force, which kind of motion will the charge undergo? & 13% Part (e) Express the centripetal acceleration of the particle in terms of the force F and the mass m I3% Part (f) Calculate the magnitude of a, in meters per square second L 13% Part (g) Express the radius, R, of the circular motion in terms of the centripetal acceleration a and the speed v 13% Part (h) Calculate the numerical value of the radius R, in metersExplanation / Answer
given
V = - 740 i ,
B = - 0.55 j
F = q ( V X B )
= - 9.5 X 10-17 X ( 740i X (-0.55k ) )
= - 3.866 X 10-14 j
a )
force is acting in downward direction
b )
the magnitude of force is F = q V B
c )
F = q V B
= 3.866 X 10-14 N
d )
here it is cross product
so it is resluts in " Uniform Circular Motion "
e )
a = F / m
= q V B / m
f )
a = F / m
= 3.866 X 10-14 / 8.2 X 10-26
a = 4.714 X 1011 m/sec2
g )
a = V2 / R
R = V2 / a
= m V2 / q V B
R = m V / q B
h )
R = m V / q B
= 8.2 X 10-26 X 740 / 9.5 X 10-17 X 0.55
R = 1.161 X 10-6 m