Part 1) a mass 10 executes circular motion in the vertical plane (e.g., a mass a
ID: 1534994 • Letter: P
Question
Part 1) a mass 10 executes circular motion in the vertical plane (e.g., a mass at the end of a string) with a velocity 15.5 (m/s). What are all the forces acting on the mass at the top of its trajectory and also the bottom of its trajectory? Part 2) a mass 13 is confined to a rough rotating platter, at a distance 5 from the center; the platter has a rotational angular velocity 14 (rad/s). Identify all the forces acting on the mass, and write the equation of motion at the time when the mass is located along the negative x-axis at a distance of 4 meters (recall that velocity=angular velocity times radius) Part 1) a mass 10 executes circular motion in the vertical plane (e.g., a mass at the end of a string) with a velocity 15.5 (m/s). What are all the forces acting on the mass at the top of its trajectory and also the bottom of its trajectory? Part 2) a mass 13 is confined to a rough rotating platter, at a distance 5 from the center; the platter has a rotational angular velocity 14 (rad/s). Identify all the forces acting on the mass, and write the equation of motion at the time when the mass is located along the negative x-axis at a distance of 4 meters (recall that velocity=angular velocity times radius)Explanation / Answer
Given
mass m = 10 kg,
in vertical circular motion with velocity v= 15.5 m/s
we know that when a body in circular motion as long as it is in circular motion the force will act towards the centre called centripetal force where ever the body is either at tthe top or at bottom
so the forcea acting on the mass are
at bottom
F = Fc - mg
mv^2 /r - mg
at top
F = -(Fc+mg)
= -(mv^2/r+mg)