Assuming that the tungsten filament of an incandescent light bulb is an ideal bl

Question

Assuming that the tungsten filament of an incandescent light bulb is an ideal blackbody, determine its peak wavelength (in nanometers) if its temperature is 3150K. lambda_max = nm Why does your answer suggest that more energy from a lightbulb goes into heat than light? The visible light gets converted to heat as it goes through the glass envelope. Electric current generates a lot of heat as the electrons collide with the metal atoms. The peak is well into the IR region of the EM spectrum. While the peak is in the visible region of the EM spectrum, there is a lot of area under the curve in the IR.

Explanation / Answer

by wien displacement law

lambda*T = 2.898 x 10^-3 m-K

T = 3150 K

lambda = 9.2 x 10^-7 m = 920 nm

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