In the circuit to the right an ideal battery is connected to three identical bul
ID: 1566486 • Letter: I
Question
In the circuit to the right an ideal battery is connected to three identical bulbs. a. Rank the brightness of the bulbs. b. If bulb A is unscrewed from its socket. what happens to the current through point 6? Explain. A wire is now connected from point 6 to point 4 and remains in place for the following: C. What happens to the brightness of each bulb? Explain. d. What happens to the potential difference across bulb B? Explain. e. What happens to the potential difference across bulb C? Explain. f. What happens to the potential difference between points 6 and 2? Explain.Explanation / Answer
4. a)the ideal battery is parallel to the bulb b&c and bulb a.so the voltage across the a is same to battery but b and c are in series.the voltage drop across b and c is equal to battery.meand v=vb+vc
because bulb a glow brightly b and c will glow with less brightness a>b=c
b)current at point 6 is comming from battery after this point in the circuit current get deviated.so even bulb a unscrewed, it does not effect the current at point 6 in the given circuit.
5.a)if point 6and 4 connected the bulb c will be parallel to battery as bulb a.
the bulb b is almost shortened,means maximum current must pass through the parallel connection of bulb b so it does not glow brightly. brightness is more in a and c . a=c>b
apply kirchhoff's loop rule to find voltage across bulb
c)the voltage across the bulb c is vc=v(voltage of battery)
b)the voltage across the bulb a is va=v
-va+vb+vc=0
vb=0
almost the bulb b does not glow because the voltage across bulb b is zero.