Consider the circuit shown in the figure. What power is dissipated by the entire

Question

Consider the circuit shown in the figure. What power is dissipated by the entire resistor circuit? a. 44 W b. 28 W c. 56 W d. 112 W What is the equivalent capacitance of the combination shown? a. 29 mu F b. 10 mu F c. 40 mu F d. 25 mu F A charge of 10 nC is distributed uniformly along the x-axis from x = -2 m to x = +3 m. Which of the following integrals is correct for the electric potential (relative to zero at infinity) at the point x = +5 on the x-axis? a) integral^3_-2 90 dx/x b) integral^3_-2 90dx/(5-x) c) integral^3_-2 18dx/x d) integral^3_-2 18dx/(5-x) e) integral^3_-2 90dx/(5+x)

Explanation / Answer

24) Three 24 ohms are parallel.

So, 1/R = 1/R1 + 1/R2 + 1/R3 = 3/24

So, R = 8 ohm

Now, two 4 ohm are in parallel.

1/R = 1/R1 + 1/R2 = 2/4

So, R = 2 ohm

Now, 2,8,3 ohm are in series.

So, R = R1 + R2 + R3 = 2+8+3 = 13 ohm

Therefore, power dissipated, P = Vsquare/R = 24*24/13

P = 44 W

Ans: Option (a)

25) 4 capacitors of 20microF are parallel.

So, Cp = C1 + C2 + C3 + C4 = 80 microF

This 80 microF is in series with another 80 microF.

So, Ceq = C1.C2/(C1+C2) = 80*80/160 = 40 microF

Ans: Option (c)

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