Please answer the questions with details. No short cuts because I will not be ab
ID: 1572400 • Letter: P
Question
Please answer the questions with details. No short cuts because I will not be able to understand it.
I already have the solution, I want to be able to solve a question like that in perfect way.
Thank you so much!!!
Represent and Reason A metal sphere RT has a net charge of -a Coulombs. An identical metal sphere, S, has a net charge of +2g Coulombs. The magnitude of the electrical force exerted on S by R is 8 Newtons. R on S a What is the magnitude of the force exerted on R by S? Explain your reasoning. b) If you halve the distance between the spheres, what will be the force exerted by R on S? Explain your reasoning. c) If you placed a charged object whose net charge was +g Coulombs right at the midway point between R and S, what direction would the net force on the +g object point? Explain your reasoning and include a force diagram.Explanation / Answer
a)We know that the electrostatic force between two charge is given by:
F = k q1q2/r^2
Force exerted on S by R is 8 N (directed towards R), so the force exerted on R by S will be 8 N only, directed towards S.
Hence, F(on R by S) = 8 N
b)We see in the formula of force that it is inversely proportional to the square of distance between the objects, so if the distance is halved, the force will become four times.
F = 4 x 8 = 32 N
c)The net force on +q would be away from S and towards R since +q and S have positive charges and they will repel each other and R has -q charge and like charges attracts each other, so +q will tend to move towards -q and +2q is already pushing +q away. Hence the direction of net force is towards left, towards R.