Class Management Help Online HW 4 Begin Date: 2/9/2018 3:02:00 PM -- Due Date: 2
ID: 1579325 • Letter: C
Question
Class Management Help Online HW 4 Begin Date: 2/9/2018 3:02:00 PM -- Due Date: 2/19/2018 4:59:00 PM End Date: 2/19/2018 11:59:00 PM (13%) Problem 5: Consider the following circuit of three resistors (R1, R2, and R3), with batteries that have emfs fja 10.5 V and 6-36.5 V, and internal resistances ri and r 0.5 Randomized Variables e1 = 10.5V 36.5 V R2 2 1R 6.0 1.5 0.5 ©theexpert ta.com 33% Part (a) Find the current 11, in amps Grade Summary Deductions Potential 0% 100% sin(0 cotan tanOi acos) acotanOsinh) cotanh) Submissions Attempts remaining: 6 (4% per attempt) detailed view cosO 23 cosh) tanh) 0 END Degrees Radians BA DEL CLEAR Submit Hint I give up!Explanation / Answer
Applying KVL in upper loop,
e1 - i2 r1 - i1 R1 - R2 I2 = 0
6 i1 + 3i2 = 10.5 ..... (i)
lower loop,
36.5 - 0.5i3 - 1.5i3 - 6i1 = 0
6i1 + 2i3 = 36.5 ...... (ii)
KCL, i1 - i2 - i3 = 0 .... (iii)
Solving, i1 = 29/8 A Or 3.625 A
i2 = -15/4 A Or - 3.75 A
i3 =59/8 A or 7.375 A