Consider the following. (Let C1 = 23.60 ?F and C2 = 17.60 ?F.) (a) Find the equi
ID: 1587781 • Letter: C
Question
Consider the following. (Let C1 = 23.60 ?F and C2 = 17.60 ?F.)
(a) Find the equivalent capacitance of the capacitors in the figure. ?F
(b) Find the charge on each capacitor.
on the right 23.60 capacitor ?C// on the left 23.60 ?F capacitor ?C// on the 17.60 ?F capacitor ?C// on the 6.00 ?F capacitor ?C
(c) Find the potential difference across each capacitor. on the right 23.60 ?F capacitor V// on the left 23.60 ?F capacitor V //on the 17.60 ?F capacitor V //on the 6.00 ?F capacitor V
6.00 F 9.00 VExplanation / Answer
why would you have two C1s? I'll relabel the one on the right C3, and the 6uf one as C4. All C and Qs in micro Farads and coulombs.
C2 and C4 are in parallel and the capacitance is 23.6 (call it C24)
C1 and C3 are in series, as is the C2/4 equivalent, and they are all 23.6 so the total equivalent is 23.6/3 = 7.87
Total Q = CV = 7.87 x 9 = 70.8
this charge is on C1, C3, and C24
Since the 3 are equal, voltage divides equally to 3 volts on each, C1, C3, and C24.
Charge on C2:
Q = Cv = 3*17.6 = 52.8
charge on C4
Q = CV = 3*6 = 18