Part A: If we set V =0 at infinity, what is the electric potential at points A ,

Question

Part A:

If we set V=0 at infinity, what is the electric potential at points A, B, and C in the figure assuming that the source charge Q=  12nC?  (Figure 1)

Part B:

If we set V=0 at point A, what is the electric potential at points A, B, and C in the figure assuming Q=  12nC?

Part C:

If the source is replaced by a negative charge as shown, (Figure 2) which of the following choices for V=0 would make the potential at points A, B, and C have positive values?

Choice answer A:

Coice answer B: Setting V=0 at a point that is between 2cm and 3.5cm from the negative source charge would make the potential at points A, B, and C positive.

Choice answer C: Setting V=0 at a point that is farther away than 3.5cm from the negative source charge would make the potential at points A B, and C positive.

Setting V=0 at a point that is closer than 2cm to the negative source charge would make the potential at points A, B, and C positive Part A Problem 21.16 MC 12nC? If we set V = 0 at infinity what is the electric potential at points A. B and C in the figure assuming that the source charge Q = 1) (Figure Enter your three answers separated by commas. Express each answer using three significant figures Figure 1 012 Submit Hints My Answers Give Up Review Part 3.5 cm Part B If we set V = 0 at point A. What is the electric potential at points A, B. and C in the figure assuming Q = 12nC? (Figure 1) Enter your three answers separated by commas. Express your answers using three significant figures. Submit Hints My Answers Give Up Review Part Part C If the source is replaced by a negative charge as shown, (Figure 2) which of the following choices for V 0 would make the potential at points A, B, and C have positive values?

Explanation / Answer

(A) Given r =2 cm = 0.02 m , Q = 12 nC = 12*10-9C

Potential at A ,    VA= K * Q/r = 9*10^9 * 12*10^-9 / (0.02) = 5400 Volts

Potential at B , VB= K * Q/r = 9*10^9 * 12*10^-9 /0.035=3085.71Volts

Point B and C lies on equipotential surface hence Potential at C = Potential at B = 3085.71Volts

(B) Potential at A , VA' = 0 (given)

      Potential at B, VB' = (VB- VA) = 3085.71- 5400 = -2314.29 Volts

      Potential at C, VC' = VB' = -2314.29 Volts   (B and C lies on an equipotetial surface)

(C) Figure 2 is not given

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